Read e-book online An Introduction to Catalan Numbers PDF

By Steven Roman

ISBN-10: 3319221434

ISBN-13: 9783319221434

This textbook presents an creation to the Catalan numbers and their extraordinary houses, besides their quite a few purposes in combinatorics. Intended to be available to scholars new to the topic, the publication starts with extra straight forward issues earlier than progressing to extra mathematically subtle topics. Each bankruptcy makes a speciality of a particular combinatorial item counted by way of those numbers, together with paths, timber, tilings of a staircase, null sums in Zn+1, period buildings, walls, diversifications, semiorders, and more. Exercises are incorporated on the finish of booklet, besides tricks and strategies, to aid scholars receive a greater clutch of the material. The textual content is perfect for undergraduate scholars learning combinatorics, yet also will entice somebody with a mathematical heritage who has an curiosity in studying in regards to the Catalan numbers.

“Roman does an admirable activity of offering an advent to Catalan numbers of a unique nature from the former ones. He has made a superb number of issues so one can exhibit the flavour of Catalan combinatorics. [Readers] will gather an outstanding feeling for why such a lot of mathematicians are enthralled by means of the impressive ubiquity and style of Catalan numbers.”

 - From the foreword by means of Richard Stanley

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Extra resources for An Introduction to Catalan Numbers

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Since S Øn ½1;nŠ ¼ S ½1, nÀ1Š , we have    Øn  S ½1;nŠ  ¼ DnÀ1 The members of S 1½1;nŠ contain the interval [1, n] and so correspond bijectively to the members of S ½2, nÀ1Š and the members of S ½n1;nŠ contain the interval [n, n] and so correspond bijectively to the members of S ½1, nÀ1Š . For 2 k n À 1, a family F 2 S ½k1;nŠ can be decomposed into two smaller families using the nexus interval [k, n], because any interval ½i; jŠ 2 F other than [k, n] must be either disjoint from [k, n], that is, contained in ½1, k À 1Š or else contained in ½k; nŠ ¼ ½k þ 1, n À 1Š.

4 with a ¼ 2) and so Dnþ2 ¼ Cn . 4 Cn counts the number of triangulations of a convex polygon with n þ 2 sides. □ Disk Stacking Sometimes it is easier to find a characterization of one type of object in terms of another type of object whose count we already know than to directly count the original objects. Here is an example. 9 shows one way to stack equal-sized disks in the plane, a task that we often find ourselves wishing to do. Let Dn be the number of possible disk stackings, where the bottom row has n disks.

7, with the root edge having a large negative slope, we say that the triangulated polygon is in left standard position. 7. Let P n be the family of all rooted triangulated n-gons. 8, each P ∈ P n can be decomposed into a rooted triangulated polygon P‘ of size k that is in left standard position and a rooted triangulated polygon Pr of size j that is in right standard position as follows. 1) 2) 3) 4) Put the polygon in center standard position. Delete the root edge. Split the opposite vertex vk into two vertices vk0 and vk00 .

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An Introduction to Catalan Numbers by Steven Roman


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